Did you read my tips on how to study and learn Math 1300?  If not, here is a link to those important suggestions:

Here is a link to the actual assignment, in case you don't have it handy:

Note that you need to study Lesson 1 (Systems of Linear Equations) and Lesson 9 (Vectors) from my Linear Algebra & Vector Geometry book to prepare for this assignment.  I think you should find this assignment fairly straightforward if you do thoroughly study and do all the Practise Problems I give you in Lesson 9.  However, make sure that you study Lesson 1 of my book first.  It is an important review of key skills you will need throughout the course and assignments.

Don't have my book or audio lectures?  You can download a free sample of my book and audio lectures containing Lessons 1, 2 and 9:

Thoroughly study Lesson 9 in my book.  Lesson 9, question 6 is similar, and you may find Practise Problems 25 to 31 (especially 29) in my lesson very helpful in understanding the kind of things to do for this and all the questions in this assignment. 

Hint: The given triangle is half of a parallelogram with sides a and b. 

Similar to my Lesson 9, question 1.

Think about what this would mean about the arrows connecting any pair of these points.

Anytime angles are mentioned, consider the formulas for the cosine or sine of an angle between two vectors.  Which one do you think would be better here?

Just a matter of using the appropriate formulas or relationships and setting up equations to solve for k.

A challenging question, but you may find Lesson 9, question 7 in my Lecture Problems of some help.

For part (d), note that the x, and y coefficients of the given line tell you the vector normal to the line.  Which is to say if given a line ax + by = c, then n = (a,b). 

Then, rather than do what I do in my question 7, you can find the distance they want in part (e) by computing the projection of arrow QP onto n.  The length of that projection vector is the distance you desire.

I strongly recommend  that you sketch this problem out on an (x,y) graph.  Plot the x-intercept of the given line by setting y=0 and the y-intercept of the line by setting x=0.  You can then visualize the distance from P to the line by drawing a line from P perpendicular to the line.  Perhaps that will help you understand why the length of the projection vector gives you the distance in part (e).

Understand that the picture they have drawn is in three dimensions.  Visualize the x-axis running west-east on your page, the y-axis running north-south, and the z-axis rising up like a pole from your table top.  The three points they want are the x-, y- and z-intercepts.  To get an intercept, simply make the other two coordinates 0.  For example, the x-intercept is where y=0 and z=0.  Sub that into the given equation to get the coordinates of the point. Make sure you are labelling correctly which one is A, B and C.